2x^2-4x+18.2=2

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Solution for 2x^2-4x+18.2=2 equation:


Simplifying
2x2 + -4x + 18.2 = 2

Reorder the terms:
18.2 + -4x + 2x2 = 2

Solving
18.2 + -4x + 2x2 = 2

Solving for variable 'x'.

Reorder the terms:
18.2 + -2 + -4x + 2x2 = 2 + -2

Combine like terms: 18.2 + -2 = 16.2
16.2 + -4x + 2x2 = 2 + -2

Combine like terms: 2 + -2 = 0
16.2 + -4x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
8.1 + -2x + x2 = 0

Move the constant term to the right:

Add '-8.1' to each side of the equation.
8.1 + -2x + -8.1 + x2 = 0 + -8.1

Reorder the terms:
8.1 + -8.1 + -2x + x2 = 0 + -8.1

Combine like terms: 8.1 + -8.1 = 0.0
0.0 + -2x + x2 = 0 + -8.1
-2x + x2 = 0 + -8.1

Combine like terms: 0 + -8.1 = -8.1
-2x + x2 = -8.1

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -8.1 + 1

Reorder the terms:
1 + -2x + x2 = -8.1 + 1

Combine like terms: -8.1 + 1 = -7.1
1 + -2x + x2 = -7.1

Factor a perfect square on the left side:
(x + -1)(x + -1) = -7.1

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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